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Find ds/dx on the curve
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\[6xy=x^4+3\]
you mean dy/dx?
no it is ds/dx , the length of curve I think?
well its implict differentiation..not sure why ds/dx
@dpalnc please help? thanks! :-)
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ds/dx would not be the length of a curve you want arc length?
\[ds=\sqrt{(\frac{dy}{dx})^2+1}\]
get that and take the derivative with respect to x I guess
\[6xy=x^4+3\] taking the derivative of both sides with respect to x \[6y+6x\frac{\text dy}{\text dx}=4x^3\]
oh you don't need to take the derivative, just rearrange it a bit (I mistyped the arc length differential before)\[ds=\sqrt{(\frac{dy}{dx})^2+1}dx\implies\frac{ds}{dx}=\sqrt{(\frac{dy}{dx})^2+1}\]use the method Unkle outlines above
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