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Mathematics 9 Online
OpenStudy (anonymous):

Find ds/dx on the curve

OpenStudy (anonymous):

\[6xy=x^4+3\]

OpenStudy (anonymous):

you mean dy/dx?

OpenStudy (anonymous):

no it is ds/dx , the length of curve I think?

OpenStudy (anonymous):

well its implict differentiation..not sure why ds/dx

OpenStudy (anonymous):

@dpalnc please help? thanks! :-)

OpenStudy (turingtest):

ds/dx would not be the length of a curve you want arc length?

OpenStudy (turingtest):

\[ds=\sqrt{(\frac{dy}{dx})^2+1}\]

OpenStudy (turingtest):

get that and take the derivative with respect to x I guess

OpenStudy (unklerhaukus):

\[6xy=x^4+3\] taking the derivative of both sides with respect to x \[6y+6x\frac{\text dy}{\text dx}=4x^3\]

OpenStudy (turingtest):

oh you don't need to take the derivative, just rearrange it a bit (I mistyped the arc length differential before)\[ds=\sqrt{(\frac{dy}{dx})^2+1}dx\implies\frac{ds}{dx}=\sqrt{(\frac{dy}{dx})^2+1}\]use the method Unkle outlines above

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