Solve the equation in quadratic form. 4x^4=13x^2-9
I did the first step and got 4x^4-13x^2+9=0 Then I factored by grouping and got [4x^4-4x][-9x+9] and im stuck on what to do next.
Set both factors equal to zero and solve for x. Make sure to check your answers.
Even with variables left?
Yeah -9x+9=0 4x^4-4x=0
You can factor out fours and nines to make it easier
so i just take out 4x and 9? because thats what I did before and I got 4x(x and I dont know what else is supposed to be in the ( )
Once you factor out, you can divide both sides of thes equation by your factors, which eliminates them from consequence in the equation\[x-1=0\]\[ x ^{3}-1=0\]
so did you divide by four somewhere in there
the 4x(x-1) maybe?
No, I only divided the bottom equation by 4x
Oh well in the end did u get |dw:1349316902469:dw|
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