Solve the equation in quadratic form.
4x^4=13x^2-9

Question

Solve the equation in quadratic form.
4x^4=13x^2-9

anonymous · Answer

I did the first step and got 4x^4-13x^2+9=0
Then I factored by grouping and got [4x^4-4x][-9x+9]
and im stuck on what to do next.

anonymous · Answer

Set both factors equal to zero and solve for x. Make sure to check your answers.

anonymous · Answer

Even with variables left?

anonymous · Answer

Yeah 
-9x+9=0
4x^4-4x=0

anonymous · Answer

You can factor out fours and nines to make it easier

anonymous · Answer

so i just take out 4x and 9? because thats what I did before and I got 4x(x and I dont know what else is supposed to be in the ( )

anonymous · Answer

Once you factor out, you can divide both sides of thes equation by your factors, which eliminates them from consequence in the equation$$x-1=0$$$$ x ^{3}-1=0$$

anonymous · Answer

so did you divide by four somewhere in there

anonymous · Answer

the 4x(x-1) maybe?

anonymous · Answer

No, I only divided the bottom equation by 4x

anonymous · Answer

Oh well in the end did u get |dw:1349316902469:dw|