Mathematics
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OpenStudy (anonymous):
What is the simplified product of (√3)(√6)=
13 years ago
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OpenStudy (anonymous):
\[\sqrt{a}\sqrt{b} = \sqrt{ab}\]
13 years ago
OpenStudy (anonymous):
9√2
√18
3√2
3
13 years ago
OpenStudy (anonymous):
\[3\sqrt{2}\]
You got it.
13 years ago
OpenStudy (anonymous):
I do not know which answer it is
13 years ago
OpenStudy (anonymous):
Oh, well look here. You see my first post?
13 years ago
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OpenStudy (anonymous):
3√2
13 years ago
OpenStudy (anonymous):
Here:
\[\sqrt{3}\sqrt{6} = \sqrt{3 * 6}\]
13 years ago
OpenStudy (anonymous):
Now what do you have?
13 years ago
OpenStudy (anonymous):
3
13 years ago
OpenStudy (anonymous):
√3+ √12
13 years ago
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OpenStudy (anonymous):
that is my simplified answer
13 years ago
OpenStudy (anonymous):
4.24175
13 years ago
OpenStudy (anonymous):
No, please stop doing this. That is not what we are looking for.
13 years ago
OpenStudy (anonymous):
Follow me step by step. What is:
\[\sqrt{6 \times 3}\]
13 years ago
OpenStudy (anonymous):
This is my last assignment for this term.................I do appreciate the help honestly I do.
13 years ago
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OpenStudy (anonymous):
what mr.qpha?
13 years ago
OpenStudy (anonymous):
\[\sqrt{6 \times 3} = \sqrt{18} = \sqrt{ 3 * 3 * 2} = 3 \sqrt{2}\]
13 years ago
OpenStudy (anonymous):
2.44 =√6
13 years ago
OpenStudy (anonymous):
\[\sqrt{18}\]
13 years ago
OpenStudy (anonymous):
I feel so stupid
13 years ago
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OpenStudy (anonymous):
Don't ever feel stupid. It just takes seeing it over and over to realize what's happening. It's building blocks. I was in the same place, I promise you that ;)
13 years ago
OpenStudy (anonymous):
well I am almost 50yrs old and never learned algebra in high school
13 years ago
OpenStudy (anonymous):
so did I get it right?
13 years ago
OpenStudy (anonymous):
I have a 4.0gpa but now this term because of Algebra
13 years ago
OpenStudy (anonymous):
Yes, but sqrt(18) simplifies though. What I do is called a "prime factorization".
13 years ago
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OpenStudy (anonymous):
not this term that is
13 years ago
OpenStudy (anonymous):
I cannot thank you enough!
13 years ago
OpenStudy (anonymous):
I have more.................problems to solve
13 years ago
OpenStudy (anonymous):
|dw:1349330370601:dw|
13 years ago