Question

How do I factor 8y^3-1000z^6?

Answer 1

let me see

Answer 2

I got to 8(y^3-125z^6) but I don't know where to go from there.

Answer 3

8(y-5z^2)(y^2+5yz^2+25z^425z^4)

Answer 4

8(y^3 -125z^6) = 8(y-5z^2)(y^2 + 25z^4 + 5yz^2)

Answer 5

Yes but how did you get that? I'm confused on the factoring part.

Answer 6

the second bracket can be again factorized...
do it usself its quadratic in y

Answer 7

u mean factor out y^3?

Answer 8

\[a ^{3} - b ^{3} = \left( a-b \right)\left( a ^{2} + b ^{2} +ab \right)\]

Answer 9

@ineedhelp911 got it!!

Answer 10

let me try it

Answer 11

this is difficult. where did the 5zy^2 come from?

Answer 12

ab part u multiply the 2 things ...

Answer 13

ohhhh

Answer 14

Difference of cubes
\[8y^3-1000z^6=(2y)^3-(10z^2)^3\]