I NEED HELP! (algebra) You have $4.10 dollars consisting of nickels and dimes. There are 30 coins in total. How many of each coins do you have?

Question

anonymous · Answer

are u sure its nickels and dimes?

anonymous · Answer

Not possible... even if you maximized it (which would be 30 dimes 0 nickels) you wuld end up with $3.00.

anonymous · Answer

Exactly
Ash is right

anonymous · Answer

its nickels and quarters...sorry

anonymous · Answer

lol ok

anonymous · Answer

im an idiot...

anonymous · Answer

Don't Say That.. It's Ok Im Honeslty Stumped Well Dont wanna really fdo the ques but ya

anonymous · Answer

I'll help you set up the problem.
The total amount of money is 5(the value of a nickel) times the number of nickels, and 25(the value of a quarter) times the amount of quarters.
$$5n + 25q = 410$$
This second equation is the sum of nickels and quarters which they tell you is 30
$$n+q = 30$$

anonymous · Answer

so solve for which variable?

anonymous · Answer

Both but you can solve for either of them first.

anonymous · Answer

i solved for 25q first and i got.164

anonymous · Answer

try using substitution. use the second equation, solve for n then substitute that into the first equation. Then solve for q.

anonymous · Answer

i get n=29 which isn't possible... right?

anonymous · Answer

Show your work, I believe your algebra might've gone awry somewhere.