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Mathematics 24 Online
OpenStudy (anonymous):

9xy^3/18x^5 y^8?

OpenStudy (anonymous):

Do you see a common factor in the coefficients?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

Divide that, what do you get?

OpenStudy (anonymous):

Are you there @shivraj?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

9/(2*9) 1/2

OpenStudy (anonymous):

so what would that be in the whole context of the equation?

OpenStudy (anonymous):

1/2x^-4y^-5

OpenStudy (anonymous):

oh wait wait, where'd we get that negative? it should be 1/(2x^4y^5)

OpenStudy (anonymous):

1/(2x^4y^5)

OpenStudy (anonymous):

yeah. that's now your final answer, because there's nothing else to divide by. do you understand it?

OpenStudy (anonymous):

so look at the coefficients first, unless you can factor it out. (but that's a totally different problem we don't need to worry about right now)

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