What real numbers are excluded from the domain of the following function?
g(x)=7x+12/x^2+3x+7
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[g(x)-\frac{ 7x+12 }{ x^2+3x+7}\]
OpenStudy (anonymous):
anything x which makes the denominator zero will be excluded. you have to solve:\[x^2+3x+7=0\]to find them.
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
this one won't factor so use the quadratic formula to get the zeros.
OpenStudy (anonymous):
i am right now :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hint...you're going to run into trouble....
OpenStudy (anonymous):
....
OpenStudy (anonymous):
what did you get?
OpenStudy (anonymous):
can't figure it out! -_- help please?
OpenStudy (anonymous):
ok. the discriminant (the part of the quadratic under the square root sign) will be a negative number. Since you can't take the square root of a negative number there are no real solutions that make the denominator zero. i.e, there are no real numbers, x, which make the denominator zero.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so, no matter what real values x takes, this function will accept it :) The domain is:\[x \in \mathbb{R} \]no real values are excluded.