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I need help finding the derivative of f(x)=26-(Sec^3(4x))
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I know that the 26 goes away. But what do i do with the rest???
Use Chain Rule.
I know how to use it in other problems but idk how to se it up here
Outer function is the secant function, x is the inner function.
you mean 4x? I got \[12Sec^24x\]
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It should be: \[-12\tan(4x)\sec^3(4x)\]
Do you know the derivative of sec(x)?
Sec(x)Tan(x) ohh, I see what you did. But why is the power 3? Isn't it suppoased to be one less?
Nope, do you see how you got secxtanx from secx? It doesn't decrease for certain trig functions.
oh, ok. Thank you
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