Question

help me solve this!
(3x^2 +3)(x^2 -1) -(x^3 +3x^2 +2)(2x) / (x^2-1)^2

Answer 1

i got:

Answer 2

3x^4-3x+3x^2-3-2x^4+6x^2+4x / x^4-2x^2 +1

Answer 3

ahh , i see where i messed up

Answer 4

\[(\frac{(3x^2+3)(x^2-1)-(x^3+x^2+2x^2+2)}{(x^2-1)^2}\]

Answer 5

(x^3+x^2+2x^2 +2)(2)

Answer 6

that is the top right of the numerator

Answer 7

so only the second part is a fraction?

Answer 8

oh my gosh, it came out all wrong lol

Answer 9

[((3x^2+3)(x^2−1)−(x^3+3x+2)(2x))/(x^2−1)^2\]

Answer 10

there we go

Answer 11

yea, i figured out my mistake, thanks!