Question

How do I solve this?
\[-7\sqrt[2]{3x-8} + 3 = -4x + 7\]

Answer 1

\[-7\sqrt[2]{3x-8} + 3 = -4x + 7\]

Answer 2

\[-7\sqrt{3x-8}=-4x+4\\ \sqrt{3x-8}=\frac{-4x+7}{-7}\] then square both sides.

Answer 3

But there is a 2 infront of the square root of 2x-8

How do i get rid of that?

Answer 4

You want to start first by solving the squareroot.

Answer 5

Don't you think that 2 simply means square root.

Answer 6

@imron07 is right. if there were a 3 there it would mean ^(1/3). The 2 just means ^(1/2) which is the same thing as square root

Answer 7

Oh that makes so much sense. Thanks guys, I really appreciate it.