Question

A thin non conducting ring rotating about an axis through its center and perpendicular to the plane of the ring. What is the current of the ring?

Answer 1

Not enough information here I think to answer it.

Answer 2

So we know that current equals charger over time. If the charge is evenly distributed as lamda then lamda is the the charge over the area or in this case the circumference of the ring which would be 2pi R. So the charge would be 2 pi lamda R. Since one over T is the frequency F, we now have everything to find the current. Current is then 2 pi lamda r f. Since angular speed is 2 pi f we can say the current is r lamda omega.

Answer 3

Wait, you said this was a nonconducting ring? I'm not sure I understand the question anymore, is this two rings or one? Draw a picture.