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integration of u^2 sinha(t-u) du
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\[ \int u^2 \sinh a(t-u) \; du\]
how will i derive
try integration by parts
Woops!! this doesn't have closed form in elementry functions http://www.wolframalpha.com/input/?i=integrate+u^2+sinh%28a%28t-u%29%29+du
but it doesn't show the steps
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and i am little weak in it
hold on ... i'll check again.
sure
you sure that 'a' is there?
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yes
the problem is from the book of laplace transformation by spiegel
Use Integration by parts \[\int u^2 \sinh (a(t-u)) du\] \[u^2\cosh (a(t-u))-\int \frac{d}{du} u^2 \times \int (\sinh (a(t-u))\] \[u^2\cosh (a(t-u))/(-a)-\int 2x \times \sinh (a(t-u))/(-a)\] Now apply by parts on second term
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