Question

prove that:
\[\frac{ \tan \theta - \cot \theta }{ \tan \theta + \cot \theta } = 2\sin ^{2} \theta\]

Answer 1

Correcrtion:
\[\frac{ \tan \theta - \cot \theta }{ \tan \theta + \cot \theta } = 2\sin ^{2} \theta-1\]

Answer 2

Try writing \(\tan\theta\) as
\[\frac{\sin\theta}{\cos\theta}\]
and \(\cot\theta\) as
\[\frac{\cos\theta}{\sin\theta}\]
and then simplify.

Answer 3

Can u do @Beatles?

Answer 4

yup.

Answer 5

\[\frac{ \sin \theta - \cos \theta }{ \sin \theta + \cos \theta }\]

Answer 6

this.

Answer 7

?

Answer 8

Beatle, when they say "prove", you want to try and alter one side of the equation and make it look like the other. Don't change both sides. :D