Suppose 2 to the power of n is a prime number. What must be the value of n? Explain how you know.
Hmm well I guess we can start by saying that we know what n CANNOT be. n cannot be an integer greater than 0. 2 raised to any (positive integer) will result in an even number. All even numbers larger than 2 are not prime. So where do we go from there? Hmmmmm...
Also, 2^0 = 1 1 is not a prime number, so then n also cannot equal 0. Hmmmm.
If we are looking for integer solutions, then that will rule out all fractional exponents. and all negative exponents as well. I think that leaves us with one possible value for n! :D And I made a mistake on my first post. It looks like n would have to be 1. 2^1 = 2 2 is a prime number. So in my first post I shouldn't said, n>1 is excluded. Ok hope that helps! :)
thanks
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