Question

how about f(x)=(x^3 -8)/(x-2) when x approach 2

Answer 1

should i factorise first?

Answer 2

Yes!

Answer 3

Remember how to factor out a term when you have the sum or difference of cubes? :)

Answer 4

its factorise of x^3-8 = (x-2)(x^2-1)

Answer 5

i can't factorise it..

Answer 6

8 = 2^3
Difference of cubes looks like this:
\[a^3-b^3=(a-b)(a^2+ab+b^2)\]

I think that's how it goes at least XD I'll check to make sure..

Answer 7

Ya :D
So you have x^3 - 2^3,
a=x
b=2

Can you factor it using the formula i posted? c:

Answer 8

Confused? :o

Answer 9

okk

Answer 10

i got d answer..thanks