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Let k and n be positive integers, with k < n. Write n! -- k! without using factorials; simplify your answer.
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\[\frac{n!}{k!}\]
n! = n(n-1)(n-2)....(n+k-n+1)k! or you can take n-k= p as n>k n!= (p+k)! = (p+k)(p+k-1).....(p+k-(p-1))k! then put p= n-k
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