Solve the equation for the exact values x o

Question

anonymous · Answer

So first you want to convert it into sine and cosine:$$\frac{6}{\sin(x)\cos(x)}=\frac{1}{cos(x)}$$

anonymous · Answer

ok.. I'm listening. trying to follow along but i'm loss

anonymous · Answer

Hmmm actually when trying that I got something which didn't make sense.

anonymous · Answer

What class is this?

anonymous · Answer

trig

anonymous · Answer

It's strange because when I simplify the equation a bit I get:$$6=\sin(x)$$However it's impossible for that to happen because $-1\leq \sin(x) \leq 1$.

anonymous · Answer

this is so overwhelming for me.

anonymous · Answer

my notes seem to make since once i get home

anonymous · Answer

not make since

anonymous · Answer

What I'm saying is that $\sin(x)$ can only be some value between 1 and -1... it can't be 2, 3, or 6 because they are all values not in between -1 and 1.

anonymous · Answer

so this would be no solution right?

anonymous · Answer

would it be safe to say that?

anonymous · Answer

I don't think there is a solution that is a real number between 0 and 2pi.

anonymous · Answer

ok that works for me. I couldn't get it.