Question

Solve the equation for the exact values x o
13 years ago

Answer 1

So first you want to convert it into sine and cosine:\[\frac{6}{\sin(x)\cos(x)}=\frac{1}{cos(x)}\]

Answer 2

ok.. I'm listening. trying to follow along but i'm loss

Answer 3

Hmmm actually when trying that I got something which didn't make sense.

Answer 4

What class is this?

Answer 5

trig

Answer 6

It's strange because when I simplify the equation a bit I get:\[6=\sin(x)\]However it's impossible for that to happen because \(-1\leq \sin(x) \leq 1\).

Answer 7

this is so overwhelming for me.

Answer 8

my notes seem to make since once i get home

Answer 9

not make since

Answer 10

What I'm saying is that \(\sin(x)\) can only be some value between 1 and -1... it can't be 2, 3, or 6 because they are all values not in between -1 and 1.

Answer 11

so this would be no solution right?

Answer 12

would it be safe to say that?

Answer 13

I don't think there is a solution that is a real number between 0 and 2pi.

Answer 14

ok that works for me. I couldn't get it.