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Mathematics 13 Online
OpenStudy (anonymous):

Find the zeros of the polynomial function and state the multiplicity of each. f(x) = 3(x + 9)^2(x - 9)^3

OpenStudy (anonymous):

4, multiplicity 1; 9, multiplicity 1; -9, multiplicity 1 correct?

ganeshie8 (ganeshie8):

hw did u get 4 ? the given polynomial i see, it has : -9, multiplicity 2; 9 multiplicity 3

OpenStudy (anonymous):

i ment 3

OpenStudy (anonymous):

**3

ganeshie8 (ganeshie8):

ohhk got u, but 3 is not a zero

ganeshie8 (ganeshie8):

for 3 to be a zero of polynomial, we should have (x-3) as factor.

OpenStudy (anonymous):

oh i see im going to get see if i get the same thing as u

ganeshie8 (ganeshie8):

ok :) but this is a q, we can answer just by looking at the polynomial. 1) i see, (x+9)^2 as a factor, so -9 is a zero, with multiplicity of 2

ganeshie8 (ganeshie8):

2) i see, (x-9)^3 as a factor, so 9 is a zero, with multiplicity of 3 thats all :)

OpenStudy (anonymous):

-9, multiplicity 2; 9, multiplicity 3 right ???

ganeshie8 (ganeshie8):

correct !

OpenStudy (anonymous):

thanks alot !

ganeshie8 (ganeshie8):

np :)

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