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Mathematics 7 Online
OpenStudy (anonymous):

NEED HELP! DON'T KNOW WHERE TO START. Large wingspanroaches can run as fast as 1.50m/s in short bursts. Suppose you turn on the light in a cheap motel and see one scurrying directly away from you at a constant 1.50m/s as you move toward it at 0.80m/s. If you start 0.90m behind it, what minimum constant acceleration would you need to catch up with it when it has traveled 1.20m, just short of safety under a counter?

OpenStudy (anonymous):

directly away from 1.50m/s toward it at 0.80m/s 0.90m behind it, minimum constant it has traveled 1.20m

OpenStudy (anonymous):

Scan complete, formulating answer...

OpenStudy (anonymous):

you would need to accelerate.....um....well, 80, so its running 1.40, so you would also need to be running at that speed, you are 90, behind it so 90 more, wich gives us 2.30 meters per hour...2.30m/s

OpenStudy (anonymous):

I mean, in what time do you want to catch the damn thing!

OpenStudy (anonymous):

brb

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