Question

Find a function whose graph is a parabola with vertex (7, 8) and that passes through the point
(6, −9).

Answer 1

The equation in vertex form is: \(\large y=a(x-h)^2+k \)
where (h, k) is your vertex.

Since (7, 8) is given as the vertex, then the equation looks like this: \(\large y=a(x-7)^2+8 \)

But you're also given that the parabola passes through (6, -9) so:
\(\large -9=a(6-7)^2+8 \)
Solve for "a" then put that back into the equation.

Answer 2

Wow. That was a lot easier that I was making it. Thank you very much!

Answer 3

I'm pretty sure my instructor showed me the hard way of doing it. You're lucky AdriRules