Question

How would the graph of y=2x^3-3x^2+1/x+3 look as its end behavior model?

Answer 1

end behavior model? I don't know that...

Answer 2

i found one real root -0.5 at y=0

Answer 3

it looks ugly

Answer 4

ok what does ugly look like a parabola

Answer 5

thanks for tryimg

Answer 6

Only -0.5 is the only real root...

Answer 7

ok I think i found what the graph is thanks to both of you :)

Answer 8

the graph looks like two parabolas

Answer 9

welcome:)

Answer 10

um how did you get -.5 though

Answer 11

\[y = 2x ^{3}-3x ^{2}+1/x+3\]
Multiply x on both sides
\[xy = 2x ^{4}-3x ^{3}+1+3x\]
\[y = (2x ^{4}-3x ^{3}+1+3x) / x\]
\[y = [(2x+1)(x ^{3}-2x ^{2}+x+1)] / x\]

Answer 12

So, \[x \neq 0\] and \[x=-1/2\]

Answer 13

got it?