Question

how you would factor 15x^4+ 50x^3– 40x^2?

Answer 1

5x^2(3x^2 + 10x - 8)

does this help ?

Answer 2

yes

Answer 3

:)

Answer 4

Yo dawg, I herd u like factoring, so I put a greatest common factor in your factors so you can factor while you factor.

Answer 5

lol XD

Answer 6

so can you factor this : 5x^2(3x^2 + 10x - 8) completely now ?

Answer 7

5x^2(x+4)(3x-2)?

Answer 8

Now find the values of x for which y becomes zero...

Answer 9

I mean *the equation becomes zero

Answer 10

Did you understand what I said?

Answer 11

not rly :/

Answer 12

Let 5x^2(x+4)(3x-2) = y
When does y become zero?

Answer 13

i dunno

Answer 14

y becomes zero when
5x^2=0 or x+4=0 or 3x-2=0

Answer 15

So, y becomes zero when x=0 or x=-4 or x=2/3..These are the roots of the equation..
got it?

Answer 16

sorta

Answer 17

Ask now if you have any doubt...

Answer 18

I think I got it.........I'm just thinking

Answer 19

-24 (a*c = -24). This can be achieved with 12x-2x, as 12*-2 = -24.

=5x^2(3x^2+12x-2x-8)
= 5x^2[(3x(x+4)-2(x+4)]
= 5x^2(3x-2)(x+4)
Factors are 5x^2, (3x-2), (x+4)

Answer 20

she just needed to factor it ..
5x^2(x+4)(3x-2) this is a right answer

Answer 21

Oh sorry:(
I think I messed it up.