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y=tan(2x-x^3) u=2x-x^3 find the derivative
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|dw:1349726073922:dw|
AM I RIGHT
use www.wolframalpha.com to check yourself
d/dx (2x-x^3) =?
2-3x^2
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yes
so whats your answer now ?
but we need to use the chain rule right so 2-3x^2=0-6x again chain rule so 6
i mean -6
u do d/dx(2x-x^3) only once, right ? its just a function of x, not a function of function of x so, no chain rule there
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what do u mean by function of function of x
like sin(x^2) is function of function of x sin x is just function., x^2 is just function chain rule applies to function of function of x
ohk now i get it thx for ur patience and help
ok, so the answer here u get is ?
sec^2(2x-x^3))(2-3x^2)
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correct :)
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