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OpenStudy (anonymous):
k(x)= x^5 + 3x - 2 Let k^-1 be the inverse of K. Find (k^-1)'(2)
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OpenStudy (anonymous):
k(2)= 45 k'(x)=5x^4 + 3 So would you just plug in 45 for the derivative of x?
OpenStudy (anonymous):
I think you have to find the inverse of the dirivative first, then plug in 2 for x
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