Question

solve for 0:
(x^5)+(x^3)-6x = 0

Answer 1

how do you solve with powers to 5?

Answer 2

\[x ^{5}+x ^{3}+-6x=0\]\[x(x ^{4}+x ^{2}-6=0\]

Answer 3

sorry, i meant factor x

Answer 4

\[x(x ^{2}+3)(x ^{2}-2)=0\]\[x=0\]\[x=\sqrt{2}\]\[x=\sqrt{3i}\]

Answer 5

so real roots are 0, and there are imaginary?

Answer 6

thanks

Answer 7

5 roots,
0, -sq rt 2, sq rt 2 (these are real)
i(sq rt -3). i(-sq rt -3) imaginary.