Solve using a system of equations:
There is a collection of nickels and dimes worth $3.30. There are 42 coins in all. How many are there of each kind?
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OpenStudy (aripotta):
5n + 10d = 330
n + d = 42
OpenStudy (anonymous):
n is the number of nickels and d is the number of dimes.
OpenStudy (aripotta):
so you gotta use the second equation to solve for d
OpenStudy (aripotta):
or n, but i would do d
OpenStudy (aripotta):
so what does d equal?
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OpenStudy (anonymous):
D=576
OpenStudy (aripotta):
no, what you gotta do it find out what d is compared to n.
so it's n + d = 42. what you do with that is subtract n from both sides to get d = 42 - n
OpenStudy (aripotta):
and then you can substitute 42 - n for d in the first equation
OpenStudy (aripotta):
so 5n + 10d = 330 would be 5n + 10(42 - n) = 330.
is this making sense?
OpenStudy (anonymous):
Yes, but we have to have a system of equations
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OpenStudy (aripotta):
the first thing i posted was our system of equations
OpenStudy (aripotta):
now we're solving it
OpenStudy (anonymous):
Oh right sorry
OpenStudy (aripotta):
so do you know what to do from there? from 5n + 10(42 - n) = 330?
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
so just distribute and then solve from there?
OpenStudy (aripotta):
yea, distribute the 10 into the parentheses and then solve for n and once you know how many nickels there are, just substitute that for n in the second equation and solve for d