Question

sqrt x+10 = x-2

Answer 1

\[\sqrt{x+10}=x-2\]

Answer 2

you first need to get rid of the radical.

Answer 3

so square both sides.

Answer 4

ok

Answer 5

so you should have x+10 = x^2-4x-4 ?

Answer 6

now move your terms all to one side and set it equal to 0 and factor or use the quadratic to solve for x

Answer 7

ok

Answer 8

actualy... i typoed.. it should be \[x+10=x^{2}-4x+4\]

Answer 9

ok i was confused trying to work that out

Answer 10

and the only reason i move to the right is cause I dont want to multiply by a negative 1.

Answer 11

\[x ^{2}-5x-6=0\]

Answer 12

you know how to factor or do the quadratic?

Answer 13

i have my text book here, these confuse me so much

Answer 14

ok. i would factor this. so you set up parens.. ( )( ) right? fill them with (x )(x ). now we are looking for 2 numbers that multiply to 6 and add to -5

Answer 15

so 2 and 3 seem to work nice.. but they are not gonna get us to where we want because of the negative 5. so we try 1 and 6. (x 1)(x 6) right?

Answer 16

so 2 and 3

Answer 17

ok

Answer 18

now since we know we a negative 5.. we know that 6 has to be negative. so (x+1)(x-6)

Answer 19

so (x+1)(x-6)

Answer 20

solve those as separate equations .. x-6=0 and x+1=0

Answer 21

x=6 x=-1

Answer 22

yep. now.. the most important.. you need to plus these numbers back into the equation.. to check if both answers work.

Answer 23

ok

Answer 24

\[\sqrt{-1+10} =-1 - 2\]

Answer 25

\[\sqrt{6+10} = 6-2\]

Answer 26

sqrt9=-3 sqrt16 = 4

Answer 27

so x = 6 is your only answer? does that make sense?

Answer 28

\[\sqrt{9} =3 \neq -1-2 = -3\] \[\sqrt{16}=4 = 6-2=4\]