Question

helllppp !
A rule in terms of 'n' for the sum of the first 'n' even even positive integers is __?_
:/ !!!

Answer 1

\[\sum_{k=1}^n2n=2\sum_{k=1}^n k\]is a start

Answer 2

unless you are unfamiliar with this notation
the sum of \(n\) integers is \(\frac{n(n+1)}{2}\) so the sum of the first \(n\) even integers is twice that, namely \(n(n+1)\)

Answer 3

so how would i know what to insert into the eq.? pretty confused on how u picked 2

Answer 4

..