Question

If :
\(\color{blue}{\text{2 + 6 + 10 + 14 + 18 + 22 + 26 + 30 + 34 + 38 = 200}}\),

Then, \(\color{red}{\text{Add}}\) any \(\color{cyan}{\text{Five}}\) numbers and get \(\color{green}{100}\)..

Answer 1

i dont really understand the question:|

Answer 2

Add any of the 5 numbers from 2, 6, 10, 14, 18, 22, 26, 30, 34, 38 and get the sum as 100..

Like:

38 + 34 + 10 + 18 = 100 (But these are 4 numbers sum only)..

Getting @Coolsector

Answer 3

yes ty

Answer 4

6+10+22+28+34=100

Answer 5

oh..... no 28

Answer 6

Ha ha ha ha... @sauravshakya

Answer 7

Is there something to do with its pattern.

Answer 8

Every number is average

Answer 9

impossible i think

Answer 10

Just add any 5 numbers, to get result as 100..

I am unable in this...

Answer 11

@sara12345 , it is impossible only until we don't get the answer for this..

If we get that, then it is possible...

Answer 12

we can prove its impossible il try

Answer 13

And I am not typing...

Answer 14

Have you deleted your comment ?? @hartnn

Answer 15

@waterineyes i don't think i will find a single post where you have commented and then NOT written that you were not typing.....
yes, i just asked whether we can repeat numbers....

Answer 16

getting 90 and 110, but not 100

Answer 17

We can't repeat numbers @hartnn ..

Answer 18

Well I can prove it is not possible.

Answer 19

I can show you that single post if you are looking for the post ..@hartnn

Answer 20

no, i am not looking :P haha..

Answer 21

Oh My God my english...!!!

Answer 22

Let the numbers five numbers be
2+(n1-1)4 , 2+(n2-1)4 , 2+(n3-1)4 , 2+(n4-1)4 , 2+(n5-1)4
=>4n1-2 , 4n2-2 ,4n3-2 , 4n4-2 , 4n5 -2
Now,
For the sum to be 100
4(n1+n2+n3+n4+n5)-10=100
4(n1+n2+n3+n4+n5)=110
Now, 110 is not divisible by 4
Thus, NOT POSSIBLE.

Answer 23

What! NOBODY got it

Answer 24

i got it

Answer 25

i like ur proof,

Answer 26

Modified slightly :

let the numbers five numbers be
2+4n1 , 2+4n2 , 2+4n3 , 2+4n4 , 2+4n5

Now,
For the sum to be 100
4(n1+n2+n3+n4+n5)+10=100
4(n1+n2+n3+n4+n5)=90
Now, 90 is not divisible by 4
Thus, NOT POSSIBLE.

Answer 27

see,i told ya, 90 and 110 are possible, not 100...and now they proved it :)
nice proof saura :)

Answer 28

@waterineyes did u get it?

Answer 29

I am still waiting for someone's reply...

Answer 30

And yes I got the proof of both of you and I liked it...

Nice...

Answer 31

i hope he doesn't write , that he is not typing

Answer 32

that was funny ;p

Answer 33

I don't think so at this time...

Answer 34

May be he will come up with 3rd method to prove the above...

Answer 35

there is only one method so far, saura's !

Answer 36

And sara's

Answer 37

is it only i or everone feels that the names rhyme....sauras and saras....

Answer 38

phonetically they're diff

Answer 39

jhonny! you were writing something ! ?
plz feel free to express your opinion, we are waiting....

Answer 40

2+6+22=30
14+26=40
22+34+14=70
38+10=48
6+14+30=50
38+22=60
38+14+22=74+18+6=98

YES ,THIS IS NOT POSSIBLE FROM 5 NUMBERS SURE

Answer 41

Okay I agree to all....

Thanks to all for your great time here on this post...

Answer 42

with 6 its possible

Answer 43

with 4 it is possible too...

Answer 44

with 7,8 its not possible

Answer 45

Yep with six looks possible as 112 0r 88 is divisible by 4

Answer 46

With 11 it is not possible..

Ha ha ha ha...

Answer 47

lol... 9 also its not possible

Answer 48

1 not possible too ...

Answer 49

thanker water and saura nice exercise :)

Answer 50

thanks*

Answer 51

And I am still not typing...

Ha ha ha...

Answer 52

Great thanks to you all...

You can help others now if you want...

Answer 53

0+2+6+10+14+18+22+26+30+34+38=200 so 0+14+22+38+26=100 your question is solve ok

Answer 54

Yes you can do this but this is bit different from our main question..

Adding 0 will simply solve the problem and there is no doubt in it...

I appreciate your thinking @yugraaz ...

Answer 55

not possible