7 X-men want to answer 2 separate distress calls. Each team must be at least 3 X-men. How many ways can the 2 teams be formed?

Question

lgbasallote · Answer

you can probably predict what im about to say...

"it's not that simple...."

lgbasallote · Answer

the X is just a prefix in X-men....

lgbasallote · Answer

@bhaskarbabu stop deleting your replies...you look like a fool who's afraid of making mistakes...

anonymous · Answer

no i just hate scrolling down n down that is why i delete mine because those r useless

anonymous · Answer

Can I ask a question?

lgbasallote · Answer

shoot

anonymous · Answer

Can it be like one team has 3X men and another team has 3X men

anonymous · Answer

@lgbasallote

lgbasallote · Answer

no. you have to use all 7

anonymous · Answer

Then it is 35

anonymous · Answer

i got only 7C3...that is the way you select 3persons from 7..selected is the three member team and left is the four member team...Am i right? @lgbasallote

lgbasallote · Answer

again with the answers and no solutions.....

anonymous · Answer

Yea..7C3 = 35

anonymous · Answer

7C4=35

lgbasallote · Answer

unfortunately...it's not that simple...

lgbasallote · Answer

close though

anonymous · Answer

Is it 7C3 +7C4? It is nothing but repeating every combination another time..!

anonymous · Answer

So, i don't think its right.

lgbasallote · Answer

it isn't

lgbasallote · Answer

but close enough for me to get what to do

anonymous · Answer

you got it? please share it with us..

lgbasallote · Answer

it's just 2 * 7C3

anonymous · Answer

Why 2?

lgbasallote · Answer

because the X-men are interchangeable

anonymous · Answer

interchangeable to answer the calls?

lgbasallote · Answer

case 1:

1st group - 3 members
2nd group - 4 members

case 2

1st group - 4 members
2nd group - 3 members

anonymous · Answer

u just asked to select the groups only and did'nt name them

anonymous · Answer

yes..you are right, but in your question, you only asked the no. of ways of forming teams and not no. of ways of answering the calls..thats the reason we didn't multiply the answer by 2!!

lgbasallote · Answer

no..actually you still do

lgbasallote · Answer

that's what makes these tricky

anonymous · Answer

its okay..you got it and we got it..that's what matters, isn't it?

lgbasallote · Answer

yes. this must be the first question of mine in this topic that was actually answered