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Limit X-->1 f(x) = 2x^2-x-1/3x^2+x-4?
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when i worked it out i got 3/7 ???
factor and cancel, replace \(x\) by \(1\)
\lim_{x \rightarrow 1}\frac{2x^2-x-1)}{3x^2+x-4}\] Using l'Hopital I also got 3/7
cool thanks
\[\lim_{x \rightarrow 1}\frac{2x^2-x-1}{3x^2+x-4}\]
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\[\frac{(x-1)(2x+1)}{(x-1)(3x+4)}=\frac{2x+1}{3x+4}\]
1 gets you \(\frac{3}{7}\)
yes factor top and bottom then cancel the x-1. Replace x by in 1 in 2x+1/3x+4 should equal 3/7
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