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Physics 9 Online
OpenStudy (anonymous):

An object is project upward with a 30 degree launch angle and an initial speed of 39 m/s. How long will it take for the object to reach the top of its trajectory? How high is this?

OpenStudy (anonymous):

Can anyone draw me a diagram for this and the steps on how to get to the answers?

OpenStudy (anonymous):

easiest way to solve this is to brake up the initial velocity into its y component do you know how to do this?

OpenStudy (anonymous):

|dw:1349907430452:dw|

OpenStudy (anonymous):

you need to find uy, you know U = 39 and the angle A is 30 degrees.

OpenStudy (anonymous):

Okay, I found out the height at the top of trajectory, which is 19.5. How do I calculate how long it takes to reach it? The answer is 25 seconds, but I don't know why.

OpenStudy (anonymous):

h=-1/2g*t^2 +voy*t

OpenStudy (anonymous):

I don't get it, can you explain how to find the time?

OpenStudy (anonymous):

|dw:1349908936227:dw| voy=vo*sindelta

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