Question

8sin^2 x + 6sin x = 9

Solve for 0 ≤ x ≤ 2π

Restricted (0, 2π)

Answer 1

\[\frac{ 9 }{ 2 } and \frac{ 3 }{ 2 }\]

Answer 2

It's supposed to be in radians, uhh...
I know I need the quadratic formula for it, and I'm supposed to get two values to set equal to zero, then find those values on a unit circle.

A similar problem might give me sin x - 1 = 0, so I'd solve that for sin x; sin x = 1, and then find where sin is equal to 1 on the unit circle, which would be my answer.

Answer 3

sinx = 3/4

Answer 4

Do you mind showing me how you got that answer?