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SHOW THAT THERE ARE NO TWO INTEGERS X AND Y THAT SOLVE X^2 +3Y^2=8
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Integers are whole numbers therefore looking at the equation solved for either variable neither y=sqrt((8-x^2/3) or x=sqrt(8-3y^2) will never equal a whole numbers if x and y are limited to integer values so they will never =8... probably an easier way to say that but i think that works
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