Mathematics
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OpenStudy (anonymous):
derivative: ln(xsqrt(x^2 - 1))
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OpenStudy (anonymous):
What is the derivative of ln(x) ??
OpenStudy (anonymous):
1/x
OpenStudy (anonymous):
Yep...
OpenStudy (anonymous):
let me show my first step
OpenStudy (anonymous):
Then do the derivative of \(x \sqrt{x^2 - 1}...\)
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OpenStudy (anonymous):
Yep carry on...
OpenStudy (anonymous):
1/xsqrt(x^2 - 1) times d/dx (xsqrt(x^2 - 1)
OpenStudy (anonymous):
Yep..
Good..
OpenStudy (anonymous):
Now find the derivative of xsqrt{x^2-1} ..
OpenStudy (anonymous):
should i first write it as x (x^2 - 1)^1/2
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OpenStudy (anonymous):
It is your wish..
But don't forget to use Product rule here..
OpenStudy (anonymous):
so well have (x) d/dx (x^2-1)^1/2 + (x^2-1)^1/2 + d/dx (x)
OpenStudy (anonymous):
* there instead of + right ???
OpenStudy (anonymous):
for the product rule
OpenStudy (anonymous):
At last you have written + there with d/dx(x) term..
Do you think that is right ??
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OpenStudy (anonymous):
oooh lol didnt see that ya ur right
OpenStudy (anonymous):
so well now have (x) 2x 1/2(x^2-1)^-1/2 + (x^2-1)^1/2
OpenStudy (anonymous):
Go slow need to hurry..
OpenStudy (anonymous):
these things take time lol
OpenStudy (anonymous):
Looks nice to me...
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OpenStudy (anonymous):
Combine both the results now..
OpenStudy (anonymous):
and we can reduce that to 1/xsqrt(x^2-1) [x^2(x^2-1)^-1/2 + (x^2-1)^1/2]