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Mathematics 5 Online
OpenStudy (anonymous):

derivative: ln(xsqrt(x^2 - 1))

OpenStudy (anonymous):

What is the derivative of ln(x) ??

OpenStudy (anonymous):

1/x

OpenStudy (anonymous):

Yep...

OpenStudy (anonymous):

let me show my first step

OpenStudy (anonymous):

Then do the derivative of \(x \sqrt{x^2 - 1}...\)

OpenStudy (anonymous):

Yep carry on...

OpenStudy (anonymous):

1/xsqrt(x^2 - 1) times d/dx (xsqrt(x^2 - 1)

OpenStudy (anonymous):

Yep.. Good..

OpenStudy (anonymous):

Now find the derivative of xsqrt{x^2-1} ..

OpenStudy (anonymous):

should i first write it as x (x^2 - 1)^1/2

OpenStudy (anonymous):

It is your wish.. But don't forget to use Product rule here..

OpenStudy (anonymous):

so well have (x) d/dx (x^2-1)^1/2 + (x^2-1)^1/2 + d/dx (x)

OpenStudy (anonymous):

* there instead of + right ???

OpenStudy (anonymous):

for the product rule

OpenStudy (anonymous):

At last you have written + there with d/dx(x) term.. Do you think that is right ??

OpenStudy (anonymous):

oooh lol didnt see that ya ur right

OpenStudy (anonymous):

so well now have (x) 2x 1/2(x^2-1)^-1/2 + (x^2-1)^1/2

OpenStudy (anonymous):

Go slow need to hurry..

OpenStudy (anonymous):

these things take time lol

OpenStudy (anonymous):

Looks nice to me...

OpenStudy (anonymous):

Combine both the results now..

OpenStudy (anonymous):

and we can reduce that to 1/xsqrt(x^2-1) [x^2(x^2-1)^-1/2 + (x^2-1)^1/2]

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