Question

Put this into a inequality and solve. One less than a number is greater than the product of 3 and the difference of 5 and the number.

Answer 1

Let the number be x. Maybe :\[x-1 > 3(5-x)\]is the required inequality.

Answer 2

I need to solve as well

Answer 3

\[x - 1 > 15 - 3x\]Now arranging the like terms you will get,\[x + 3x > 15 + 1\]\[4x > 16\]Dividing 4 in both sides:\[\frac{ 4x }{ 4 } > \frac{ 16 }{ 4 }\]\[x > 4\]

Answer 4

I hope you get it.