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8^(x-1) = 4
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5/3
\[8^{x-1}=4\]
can you explain how please?
is it really 5/3 ?
To solve this, use logs, since the variable is an exponent.
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I thought it was \[2^{3x+3} = 2^{2}\]
isn't it just \[\frac{ 1 }{ 8x } = 4\]
i have the answers and 5/3 is right. i just don't know how to get there
we dont need log just convert the bases to 2 same as tianz done
:D!!
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