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Mathematics 6 Online
OpenStudy (anonymous):

Not sure how to solve this: in comment.

OpenStudy (anonymous):

\[\sqrt{x+5}=8\]

OpenStudy (anonymous):

Well you wanna undo the square root so you can solve for x, so to do that you would square both sides, right?

OpenStudy (anonymous):

So it would be: \[x^2+25 = 64\]

OpenStudy (anonymous):

No, when you square a square root, all it does it get rid of the square root. So: x+5=64

OpenStudy (anonymous):

Ohhh, okay. Didn't realize that. So x=59?

OpenStudy (anonymous):

Yep.

OpenStudy (anonymous):

Okay, do you think you could help me with one more? So I understand how to do it? \[\sqrt{8x+5}= 3\sqrt{x}\]

OpenStudy (anonymous):

Yeah, im guessing you do the same thing, square both sides and you get: 8x+5=9x 5=x

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