I attached the question. Pwease help :)
the polygon is in the shape of trapezium
You know three out of the four angles of a quadrilateral, you can solve for the fourth.
all triangles have to add up to 180 degreess!! that doesnt work!!!!
this polygon is trapezium
and the area of trapezium=1/2*sum of parallels sides*height
so then its 135?
The area is irrelevant, @mayankdevnani. The four angles of a quadrilateral add up to 360º
so it doesnt make sence!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Why not?
what is the answerr?? 135?
Why do you think that?
because the triange has to add up to 180! and if you add the bigger number it s 225, but if you add the smaller one its lowere then 180!
What triangle are you seeing?
at the bottom!! if you cut off the top and make it a squaree!
This is the picture that I see from the file you posted: |dw:1350051780236:dw|
That would make a triangle and a rectangle, but that would make your situation more difficult.
yes!! so , if you cut over from c (or h) you get a triangel and a rectangle (not square soory) so i need the measure of angle J!! and js in the triangle. so h plus j plus the top right corner must equal 180. correct?
Yeah, that's fine, and what is that top right corner?
90?
|dw:1350052007637:dw| Yes, that's correct.
so, h is 135 as well?
Think about what happens to that 135º angle when you cut it like that.
of my gosh!! did it divide in half??
No. |dw:1350052088746:dw| HKJ = 90 GHJ = 135 What is GHK?
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