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Mathematics 14 Online
OpenStudy (anonymous):

Mid point help!! (attachment) plz help!

OpenStudy (anonymous):

OpenStudy (anonymous):

ini mini miny moe

OpenStudy (anonymous):

Haa ;) it dont work that way ;P

OpenStudy (anonymous):

Try it it works somtimes

OpenStudy (anonymous):

@Zarkon maybe he can answer

OpenStudy (anonymous):

Thanks!!

OpenStudy (cwrw238):

the link asks for the lengths

OpenStudy (anonymous):

how do u find that?

OpenStudy (cwrw238):

midpoint.png

OpenStudy (anonymous):

No.. i mean how do u find the lengths

OpenStudy (cwrw238):

lol - ok segment EF = square root( (5-1)^2 + (-5-(-2)^2) = square root 16+9 = square root 25 = 5

OpenStudy (anonymous):

Thanks! Are both lengths gonna b 5?

OpenStudy (cwrw238):

GH = square root (1^2 + 2^2) = square root 5

OpenStudy (anonymous):

Thanks!!! culd u help me with another problem

OpenStudy (cwrw238):

yes - i think i have time

OpenStudy (anonymous):

Ha thanks!

OpenStudy (cwrw238):

midpoint = x1 + x2 y1 + y2 ------ ------- , 2 2 here x1 = -2 , x2 = x+2 , y1 = -6 and y2 = x+3

OpenStudy (cwrw238):

gotta go now...

OpenStudy (anonymous):

if (x1, y1) and (x2, y2) are two points, then the mid point is ( (x1+x2)/2, (y1+y2)/2 )

OpenStudy (anonymous):

okk.. but which choice wuld that b? i dont see it

OpenStudy (anonymous):

what did you get?

OpenStudy (anonymous):

(x/2, (y-3)/2)?

OpenStudy (anonymous):

yep. Thats the correct answer.

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