Question

Solve sin^2 x = cos^2 x for 0 degrees less than or equal to x less than 360

Answer 1

Sin^2 x= cos^2 x 0 <= x < 360
Sub (1 - sin^2) for cos^2
sin^2 = 1 - sin^2


2sin^2 = 1
sin^2 = 1/2
----
sin = -sqrt(2)/2, +sqrt(2)/2
x = 45 degrees, 135 degrees, 225 degrees, 315 degrees

is this correct?

Answer 2

not sure about it, because:
cos^2x-sin^2x=cos2x=0
cos t=0 for t=90 and t=270
so x=45 and x=135

Answer 3

ok

Answer 4

@onegirl, looks ok..
and if you're unsure, check your answers by plugging your answers back into the original equation....