Question

solve 2sin^2 x - sin x = 1 for 0 less than or equal to c less than 360 degrees

Answer 1

2 sin^x - sin x - 1 = 0
(2sin x + 1)(sin x - 1) = 0
so sin x = -1/2 , 1

Answer 2

so only two solutions?

Answer 3

only 2 solutions for sin x
but u want values of angle x between 0 and 360 right?

Answer 4

yes

Answer 5

angle whose sine = 1/2 is 30 degrees
but its -1/2 so its in 3rd and 4th quadrants
so x = 210 , 330 degrees

Answer 6

okay

Answer 7

so 7pi/6 and 11pi/6 right?

Answer 8

yes

Answer 9

okay :)

Answer 10

arcsin 1 = 90 degrees or pi/2

so complete solution is

x = pi/2 . 7pi/6 and 11pi/6

Answer 11

okay

Answer 12

will i do this the same way you showed me?
tan^2 x - 3 = 0 for 0 less than or equal to x less than 2pi

Answer 13

yes find values of tan x, remember square root can be positive or negative.

and the tangent is positive in first and third quadrants and negative in the others

Answer 14

ok