Question

tan^2 x - 3 = 0 for 0 less than or equal to x less than 2pi

Answer 1

whats ur question?

Answer 2

my question is tan^2 x - 3 = 0 for 0 less than or equal to x less than 2pi

Answer 3

right. write tan^2(x) interms of cos2x

Answer 4

ok

Answer 5

ok im not getting this

Answer 6

first write tan^2(x) interms of cos(2x)

Answer 7

ok im not getting this

Answer 8

ok im not getting this

Answer 9

ok im not getting this

Answer 10

\[\tan^2(x) = \frac{ 1-\cos(2x) }{ 1+\cos(2x)}\]

use this formula and find the value of cos(2x)

Answer 11

ok

Answer 12

ok

Answer 13

ok

Answer 14

ok

Answer 15

umm can you explain it more?

Answer 16

\[\tan^2(x)=\frac{1−\cos(2x)}{1+\cos(2x)}\]

so
\[\frac{1−\cos(2x)}{1+\cos(2x)} = 3\]

now find cos(2x)

Answer 17

im still not getting this :/

Answer 18

@CliffSedge do you know how i can do this problem?

Answer 19

cross multiply and simplify. find cos(2x)

you should get cos(2x) = -1/2

Answer 20

ok?

Answer 21

I'll take a look at it.

Answer 22

Everything chenna showed looks fine. What part are you still stuck on @onegirl ?

Answer 23

nvm i think i got it

Answer 24

x = 0 to 2pi right?

Answer 25

thats the answer right?

Answer 26

ok?

Answer 27

are you there?

Answer 28

no. that is not the answer. you need to find the value of x.

did you get cos(2x) = -1/2 ?

Answer 29

yea

Answer 30

so x = 3pi/2, pi/6, and 5pi/6?

Answer 31

no. when does cos(t) = -1/2 ?

Answer 32

when i crossed multiply

Answer 33

I meant for which value of t, cos(t) = -1/2

Answer 34

ohh ok

Answer 35

i think i got it thanks.

Answer 36

so what is the value of x you got?

Answer 37

x = pi/4 ,3pi/4, ,5pi/4, 7pi/4

Answer 38

no. those values are wrong.

when does the value of cosine function equals to 1/2 ??

Answer 39

ok