Question

t=-0.005x^2+0.45x+125 Will this equation ever exceed the value of 141?

Answer 1

Plug in t = 141 and solve for x. What do you get?

Answer 2

umm im not sure can u explain/

Answer 3

?*

Answer 4

t=-0.005x^2+0.45x+125

141=-0.005x^2+0.45x+125

0=-0.005x^2+0.45x+125-141

0=-0.005x^2+0.45x-16

-0.005x^2+0.45x-16 = 0

Now use the quadratic formula to solve for x

Do you know the quadratic formula?

Answer 5

no..... thats what im on that im struggling with...

Answer 6

The quadratic formula is

\[\Large x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Does that look familiar?

Answer 7

no.....

Answer 8

So you haven't learned it yet?