Question

The demand function and the cost function for x units of a product are p=30/sqrt(x) and c=.95x+4750 Find value of the marginal profit when x=8100.
The value of the marginal profit when x= 8100 is

Answer 1

"demand function and the cost function for units of a product are ...and ,,," !?!

Answer 2

i edited it

Answer 3

Do you know how to find Profit?

Answer 4

not really im really confused. if you could show me step by step itll be helpful

Answer 5

Big big Hint: Relation between Revenue and Cost

Answer 6

revnue-cost

Answer 7

Yep, now what's Revenue?

Answer 8

30/sqrt(x)?

Answer 9

nevermind
im not sure

Answer 10

pretty big Hint: Relation between demand and unit!

Answer 11

for the demand function: input variable x is quantity, the output variable p is price?

Answer 12

-> R(x) = P (x) * x

Answer 13

p=30/sqrt(x) means price = 30/sqrt(quantity)

Answer 14

so 30/sqrt(8100)* 8100?

Answer 15

Can you find the Profit function now?

Answer 16

is it the equation i said?

Answer 17

P (x) = R(x) - C(x)

Answer 18

so p(x)= 30/sqrt(8100)-(.95(8100) +4750?

Answer 19

Do NOT plug the numbers in when you don't understand the concept !!!

Answer 20

okay

Answer 21

so what do i do?

Answer 22

P (x) = R(x) - C(x)
What do you understand about my explanation?

Answer 23

do you have to find the derivative?

Answer 24

R(x) = ...?

Answer 25

p(x)*x

Answer 26

Yes, now replace the function in!

Answer 27

30/sqrt(x)* X?

Answer 28

Wrong multiply:
R(x) : 30x/√x = ....?

Answer 29

do the x cancel out?

Answer 30

Note: x = √x * √x

Answer 31

so whats next?

Answer 32

So how do you cancel?

Answer 33

multiple the top and bottom by sqrt(x)?

Answer 34

R(x) : 30x/√x
=30√x * √x / √x

Answer 35

and what do we do next

Answer 36

What do you cancel out?

Answer 37

im planing on going to help with the professor by monday, but my assignment is due tonight at 11

Answer 38

would it be 30sqrt(x)

Answer 39

Yes, ( finally !!! )

Answer 40

Now, plug the value in P (x) = R(x) - C(x)

Answer 41

30sqrt(x)-.95x+4750?

Answer 42

P (x) = R(x) - C(x)
=30√x -( .95x+4750 )

Answer 43

Do you see your mistake?

Answer 44

i had to put peranthesis

Answer 45

=30√x - ( .95x+4750 )
=30√x - .95x - 4750

Answer 46

the negative sign

Answer 47

i understand

Answer 48

Yes, you need to learn writing in equation.

Answer 49

Now, how to find Marginal Profit?

Answer 50

im not sure lol

Answer 51

Why you don't know anything Profit, Revenue, Marginal ....?!!!

Answer 52

Marginal Profit P'(x)

Answer 53

i was sick so i missed the lessons, but the assignment is due tonight at 11pm which is on the computer and have to hand in on time. meeting with the professor on monday

Answer 54

(15/sqrt(x)) + 95?

Answer 55

This is not your fist post about finding Marginal, and many of solvers have already helped you out!

Answer 56

Take derivative of P (x)
-> P' (x) = ....?

Answer 57

(15/sqrt(x))+15?

Answer 58

+95*

Answer 59

P(x) = 30√x - .95x
-> P'(x) = 15/√x - .95
Thus P'(8100) = ....

Answer 60

-47/60?

Answer 61

i got it. thanks for the help