Question

what is the simplified form of x^2+6x+8/4-x^2

Answer 1

factor the numerator as \((x+2)(x+4)\) and the denominator as \((2-x)(2+x)\) then cancel the common factor

Answer 2

3. x^2 + 6x + 8 / 4 - x^2?
x+6x+2-x
6x+2 is your final answer.

Answer 3

i am fairly sure the question is
\[\frac{x^2+6x+8}{4-x^2}\]

Answer 4

im confused. would yu do distributive property for the top?

Answer 5

well yes, you would use the distributive property to factor. you get
\[\frac{x^2+6x+8}{4-x^2}=\frac{(x+4)(x+2)}{(2-x)(2+x)}\]
\[=\frac{(x+4)\cancel{(x+2)}}{(2-x)\cancel{(2+x)}}=\frac{x+4}{2-x}\]

Answer 6

omg. okay thanks.

Answer 7

yw