Question

Find the lim(x,y)-(0,0) (3x^2+3y^2) log(x^2+y^2)
The book says to turn it to polar coordinates. When I do that I get (3(r^2)) log(r^2) I don't know what to do now.

Answer 1

r^2->0 as (x,y) ->0

Answer 2

probably use l'Hopital's...?

Answer 3

yeah, I was thinking about that, but I don't know what should go on top the (3r^2) or log(r^2)

Answer 4

cool, you edited it so it's correct..

Answer 5

let's see...

Answer 6

I used 1/r^2 for the denom.

Answer 7

((ln(r^2)) ' / (r^-2) '