Question

3x^2+3x=18

Answer 1

Subtract 3x from both sides, then divide by 3, then take the square root of both sides. You'll get two answers, one being positive and one being negative.

Answer 2

hm ok .. tried all of that.... im at \[\sqrt{x^{2}}=\sqrt{6}\]

Answer 3

\[\sqrt{6-x}\]

Answer 4

very lost

Answer 5

Ok, my bad. This is what you should then do. subtract the 18. You'll get 3x^2+3x-18=0.

Answer 6

3x^2+3x=18

3x^2+3x-18=0

3(x^2+x-6)=0

Find two numbers that multiply to -6 and add to 1. They are 3 and -2, so x^2+x-6 factors to (x+3)(x-2) and we get

3(x+3)(x-2)=0

I'll let you finish

Answer 7

(3x +6)(x-3) is that right?

Answer 8

Now break up the equation into factors of 3: for ex. 3(x^2)+3(x)+3(-6)=0 Now Factor out the 3. You'll get 3(x^2+x-6)=0

Answer 9

You end up with 3(x+3)(x-2)=0 Divide both sides by 3, you end up with x= -3 and x=2

Answer 10

i think i get it! thank you very much.