Question

A bomb of mass 10kg is projected from a point time t=0,theta=37 degrees, above the horizontal with a speed =30m/s.At some point after the projection it explodes into 2 fragments,one fragment of mass 4kg is observed at (105,43)m at time t=2s.Then the position of 2nd fragment at t=2s is?

Answer 1

@experimentX

Answer 2

give it a try ... find the position of bomb without exploding at t=2s

Answer 3

I have to use this right?
\[\frac{m _{1}x _{1}+m _{2}x _{2}}{m1+m2}\]

Answer 4

for the X position

Answer 5

yeah ... center of mass will be at the position of the bomb without exploding.
first find the CM.

Answer 6

Initially it will be 0?

Answer 7

no ... find the cm at 2s .. not 0s

Answer 8

\[\frac{4 \times 105 + 6 \times x2}{10} \]

Answer 9

for X?

Answer 10

or do i have to equate to 105 itslf?

Answer 11

4x1+6x2/10=105?

Answer 12

this is just projectile motion ... what would be the position of the stone (not bomb) after 2s? with same conditions ??

Answer 13

90 sin74?

Answer 14

@experimentX ?

Answer 15

what i found is range