If f(b)=cos2B+2sinB, the numerical value of f (pi/6) is what?
Simply plug pi/6 in B
do i put my calculator in radian?
Like this: \[\Large \cos \left(2 * \frac{\pi}{6}\right) + 2 \sin \left(\frac{\pi}{6}\right)\] And yes, put it in radian.
i got 1 1/2 but thats not an answer choice
i did that
omg i was up to late x_X its 3/2
Haha, yeah, it's the same.
Do you understand?
lol oh my yes, wait another one, this one confuses me beyond belief , sin(arccos 1/2)
It's a little tough, of course. Do you have arccos in your calculator?
is it radical 3/2?
yea lol i think i just found the answer i was just studying too late last night and too stressed out to focus x.x
First, calculate arccos(½) then calculate sin( Ans )
arccos(½) = pi / 3 so sin(arccos 1/2) = sin( pi / 3 )
Does this make sense?
The answer is 0.866, by the way.
uhmm no my bro said just put it together and i got .866 and radical3/2 is equal to it
LOL yea i get it
Glad you got it. Do you have another question?
me too lol and yes! i will close this and open it!
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